Iterative Numerical Approximation
is often used instead of analytic solutions
because the application of such algorithms is much more general than symbolic
solutions. For example, consider the solution of a weak acid HA an approximate
solution is of the form
If we ignore the [H3O+] in the denominator we have the concentrated weak acid
approximation.
If the initial ionization of water can be ignored, this is the standard setup for
dissociation that we see in the text and very similar to the dimerization equilibrium we
solved using the quadratic formula.
A more accurate solution may be obtained from the simultaneous solution of the water
autoinionization equilibrium:
To solve for four unknowns we need two more equations. Defining nHA0/V = [HA]0
But the solution must be electrically neutral
And of course the acid equilibrium gives us the four equations we need
So, solving for the [H3O+] in terms of constants and initial conditions
Yields the final, although cumberson result:
Numerical Example (Iteration): Calculate the pH of 0.100M NaHSO4
Sodium ions are the conjugate acid of a strong base
Bisulfate is the conjugate base of a strong acid but the conjugate acid of a weak base!
Determine Ka of (HSO4)- from a Table (1.1 x 10-2)
Make series of 'iterated guesses' for the value of y
Result [H3O+]e = 0.028M (2 sig figs); pH = 1.55 (2 sig figs)
The equilibrium constant, taken as a dimensionless number
that is a function of temperature only, has to be referenced to a definition of the
standard state for the molecular number density. If that standard is 1 mol/L, we say the
equilibrium constant is KC, if the standard is atm pressure, the equilibrium constant is
labeled Kp
Recall the expression for KC:
The proper quotient of equilibrium partial pressures, assuming the ideal gas equation
of state (pV=nRT) is
Therefore the relationship relating the equilibrium constants references to the different
standard states is temperature dependent
This distinction is particularly important in systems where the volume is changed.
Then, the partial pressure divided by the total pressure yields the mole fraction of the
particular constituent
Only when the sum of the generalized stoichiometric coefficients in the reaction is non-zero will a change in pressure or volume affect the equilibrium mole fractions,
concentrations of course all scale with total volume for a closed system.









Iteration
trial y
[HA]0 - y
LHS
1
0 M
0.10 M
0.033166
2
0.0331166
0.066834
0.027114
3
0.027114
0.072886
0.028315
4
0.028315
0.071685
0.028081
A Review of General Equilibrium Concepts
Remember that the Numerical Value Equilibrium Constants depends on
Choice opf the
Standard State. We can forget about this in Acid / Base calculations if we choose only to use one
Standard State.
But Gases had two standard states which could be interrelated...



